Weighing of gold in a specimen

Could someone please give me the method and formula for the weighing of gold in a quartz specimen.

Thanks
Wombat

This may help you?!

http://www.gold-nuggets.org/specific-gravity-test.htm#whatis




Hi Wombat

I think he was saying that if you had looked under Gold and Its Properties Section, you would have found your answer there (about halfway down)

Jeff

Thanks Jeff. I knew that there was a formula but I could not remember what it was, A couple of mates got 2 nice little specy's yesterday and we what to know the gold content in each.
Thank again

Cheers Wombat

Yep, thanks Jeff.

Sorry, that "Thank you" was ment for Ferrousfinder

HAPPY BIRTHDAY WOMBAT!!! HIP HIP HOORAY

Hi guys,
Not to be picky , but for those interested in a bit more accuracy (if I have my figures right!) I calculated the gold in this example to be 45.25 gms (using pure S.G's.) This was done with Chris Hakes 'stab in the dark' method. The difference is only a bit over 3.3 gms but for some people a 7.3% difference (from the lower weight) may be significant.

Cheers,
Rick.

Hi im new to the site but i think this is what you want
G (gold) = (d x N x (1 - q/n)) / (d - q)

G = Weight of gold (grams)
d = Density of gold (approx. 19 gm/cubic cm)
N = Weight of nugget in air (grams)
q = Density of quartz (approx. 2.6 gm/cubic cm)
n = Density of nugget ( gm/cubic cm)

Density = (weight of nugget in air) / (weight in air) - (weight in
water)

or try this link http://www.nqminersden.com/specific.htm

Thanks Hopper
I was mainly trying to find out the forula for a mate who found a specy, but you never know I may need it sometime later my self, ( I hope)

Cheers Wombat

Wombat be careful, pays to check weight of quartz if there is similar material around find as i've known it to vary from 2.4t/m3 to 3.0t/m3plus depending on ferrous and metallic type material with quartz

Thanks mate I'll keep that in mined
Wombat